(3x-1)(x^2+2)=(3x-1)(7x-10)

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Solution for (3x-1)(x^2+2)=(3x-1)(7x-10) equation: 



(3x-1)(x^2+2)=(3x-1)(7x-10)

We move all terms to the left:

(3x-1)(x^2+2)-((3x-1)(7x-10))=0

We multiply parentheses ..

-((+21x^2-30x-7x+10))+(3x-1)(x^2+2)=0



We calculate terms in parentheses: -((+21x^2-30x-7x+10)), so:

(+21x^2-30x-7x+10)

We get rid of parentheses

21x^2-30x-7x+10

We add all the numbers together, and all the variables

21x^2-37x+10

Back to the equation:

-(21x^2-37x+10)



We get rid of parentheses

-21x^2+37x+(3x-1)(x^2+2)-10=0

We move all terms containing x to the left, all other terms to the right

-21x^2+37x+(3x-1)(x^2+2)=10

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